Question:
it's stopping distance would be roughly 80ft or 160 ft? Thanks!! ;)
Answers:
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KE = 1/2 x m x v^2
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So when all other things are equal, when a car is moving twice as fast it has four times as much kinetic energy and would therefore require four times as much distance to stop.
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160ft. Not exactly, but closer to it than 80.edit: Sorry, I was going by the formula, y=.6x2+1.1x, which is supposed to compensate for human reaction time, among other factors, and got 140ft. If you're just using the kinetic energy formula, which I suspect is where you got the first distance, then Sarge is right.
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